0.1x^2-0.001=0

Solution for 0.1x^2-0.001=0 equation:

0.1x^2-0.001=0

a = 0.1; b = 0; c = -0.001;
Δ = b2-4ac
Δ = 02-4·0.1·(-0.001)
Δ = 0.0004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.0004}}{2*0.1}=\frac{0-\sqrt{0.0004}}{0.2}
=-\frac{\sqrt{}}{0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.0004}}{2*0.1}=\frac{0+\sqrt{0.0004}}{0.2}
=\frac{\sqrt{}}{0.2}
$